5003 Praxis Practice Test Practice Question
The perimeter P of a rectangle with length / and width W is given by the formula P = 2(L + W). What is the width of a rectangle with a perimeter of 50 cm and a length of 10 cm?
Correct Answer: 15 cm
Rationale: To find the width of the rectangle, we start with the perimeter formula \( P = 2(L + W) \). Given \( P = 50 \) cm and \( L = 10 \) cm, we can rearrange the formula:
1. Substitute the known values: \( 50 = 2(10 + W) \).
2. Simplify: \( 50 = 20 + 2W \).
3. Isolate \( W \): \( 30 = 2W \) leads to \( W = 15 \) cm.
The option of 15 cm is accurate as it satisfies the perimeter equation.
Other options, such as 10 cm or 20 cm, do not satisfy the perimeter requirement when substituted back into the formula, resulting in incorrect perimeters. Thus, only 15 cm is valid.
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